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130503520481 is a prime number
BaseRepresentation
bin111100110001010011…
…1011011000011100001
3110110212000101201212112
41321202213123003201
54114232400123411
6135541423205105
712266666423045
oct1714247330341
9413760351775
10130503520481
1150389920564
1221361446795
13c3ca2c0149
1464602da025
1535dc174b8b
hex1e629db0e1

130503520481 has 2 divisors, whose sum is σ = 130503520482. Its totient is φ = 130503520480.

The previous prime is 130503520471. The next prime is 130503520487. The reversal of 130503520481 is 184025305031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85196269456 + 45307251025 = 291884^2 + 212855^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130503520481 is a prime.

It is a super-3 number, since 3×1305035204813 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (130503520487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65251760240 + 65251760241.

It is an arithmetic number, because the mean of its divisors is an integer number (65251760241).

Almost surely, 2130503520481 is an apocalyptic number.

It is an amenable number.

130503520481 is a deficient number, since it is larger than the sum of its proper divisors (1).

130503520481 is an equidigital number, since it uses as much as digits as its factorization.

130503520481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 130503520481 in words is "one hundred thirty billion, five hundred three million, five hundred twenty thousand, four hundred eighty-one".