Base | Representation |
---|---|
bin | 10010111111011010100… |
… | …000100001101110001011 |
3 | 11121202112112222100111111 |
4 | 102333122200201232023 |
5 | 132340211002104012 |
6 | 2435305542511151 |
7 | 163200063620545 |
oct | 22773240415613 |
9 | 4552475870444 |
10 | 1305041050507 |
11 | 463512718037 |
12 | 190b137354b7 |
13 | 960ac5c9a6c |
14 | 47242c94695 |
15 | 23e31789ba7 |
hex | 12fda821b8b |
1305041050507 has 2 divisors, whose sum is σ = 1305041050508. Its totient is φ = 1305041050506.
The previous prime is 1305041050447. The next prime is 1305041050513. The reversal of 1305041050507 is 7050501405031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1305041050507 - 215 = 1305041017739 is a prime.
It is not a weakly prime, because it can be changed into another prime (1305041000507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652520525253 + 652520525254.
It is an arithmetic number, because the mean of its divisors is an integer number (652520525254).
Almost surely, 21305041050507 is an apocalyptic number.
1305041050507 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305041050507 is an equidigital number, since it uses as much as digits as its factorization.
1305041050507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10500, while the sum is 31.
Adding to 1305041050507 its reverse (7050501405031), we get a palindrome (8355542455538).
The spelling of 1305041050507 in words is "one trillion, three hundred five billion, forty-one million, fifty thousand, five hundred seven".
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