Base | Representation |
---|---|
bin | 111100110001100010… |
… | …0000111001000001011 |
3 | 110110212112112211010120 |
4 | 1321203010013020023 |
5 | 4114241311303120 |
6 | 135542252314323 |
7 | 12300120354624 |
oct | 1714304071013 |
9 | 413775484116 |
10 | 130511041035 |
11 | 503930978a1 |
12 | 21363a729a3 |
13 | c3cba2428b |
14 | 64612d6a4b |
15 | 35dcb5d140 |
hex | 1e6310720b |
130511041035 has 16 divisors (see below), whose sum is σ = 208963420704. Its totient is φ = 69557303552.
The previous prime is 130511041007. The next prime is 130511041079. The reversal of 130511041035 is 530140115031.
It is a cyclic number.
It is not a de Polignac number, because 130511041035 - 216 = 130510975499 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130511040996 and 130511041014.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3014352 + ... + 3057341.
It is an arithmetic number, because the mean of its divisors is an integer number (13060213794).
Almost surely, 2130511041035 is an apocalyptic number.
130511041035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
130511041035 is a deficient number, since it is larger than the sum of its proper divisors (78452379669).
130511041035 is a wasteful number, since it uses less digits than its factorization.
130511041035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6073134.
The product of its (nonzero) digits is 900, while the sum is 24.
Adding to 130511041035 its reverse (530140115031), we get a palindrome (660651156066).
The spelling of 130511041035 in words is "one hundred thirty billion, five hundred eleven million, forty-one thousand, thirty-five".
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