Base | Representation |
---|---|
bin | 11000010011110100… |
… | …11011011001111001 |
3 | 1020200120011100002022 |
4 | 30021322123121321 |
5 | 203212102312213 |
6 | 5555020444225 |
7 | 641264324636 |
oct | 141172333171 |
9 | 36616140068 |
10 | 13051213433 |
11 | 5598084905 |
12 | 26429a9675 |
13 | 12ccb934cb |
14 | 8bb49b18d |
15 | 515bbb308 |
hex | 309e9b679 |
13051213433 has 4 divisors (see below), whose sum is σ = 13051929588. Its totient is φ = 13050497280.
The previous prime is 13051213393. The next prime is 13051213457. The reversal of 13051213433 is 33431215031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3666060304 + 9385153129 = 60548^2 + 96877^2 .
It is a cyclic number.
It is not a de Polignac number, because 13051213433 - 212 = 13051209337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13051213033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 330008 + ... + 367433.
It is an arithmetic number, because the mean of its divisors is an integer number (3262982397).
Almost surely, 213051213433 is an apocalyptic number.
It is an amenable number.
13051213433 is a deficient number, since it is larger than the sum of its proper divisors (716155).
13051213433 is an equidigital number, since it uses as much as digits as its factorization.
13051213433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 716154.
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 13051213433 its reverse (33431215031), we get a palindrome (46482428464).
The spelling of 13051213433 in words is "thirteen billion, fifty-one million, two hundred thirteen thousand, four hundred thirty-three".
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