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13051213441 = 71864459063
BaseRepresentation
bin11000010011110100…
…11011011010000001
31020200120011100002121
430021322123122001
5203212102312231
65555020444241
7641264324650
oct141172333201
936616140077
1013051213441
115598084912
1226429a9681
1312ccb93506
148bb49b197
15515bbb311
hex309e9b681

13051213441 has 4 divisors (see below), whose sum is σ = 14915672512. Its totient is φ = 11186754372.

The previous prime is 13051213393. The next prime is 13051213457. The reversal of 13051213441 is 14431215031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13051213441 - 29 = 13051212929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13051213481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 932229525 + ... + 932229538.

It is an arithmetic number, because the mean of its divisors is an integer number (3728918128).

Almost surely, 213051213441 is an apocalyptic number.

It is an amenable number.

13051213441 is a deficient number, since it is larger than the sum of its proper divisors (1864459071).

13051213441 is an equidigital number, since it uses as much as digits as its factorization.

13051213441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1864459070.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 13051213441 its reverse (14431215031), we get a palindrome (27482428472).

The spelling of 13051213441 in words is "thirteen billion, fifty-one million, two hundred thirteen thousand, four hundred forty-one".

Divisors: 1 7 1864459063 13051213441