Base | Representation |
---|---|
bin | 111100110001111011… |
… | …0000110001010110011 |
3 | 110110220110012112102221 |
4 | 1321203312012022303 |
5 | 4114303140104212 |
6 | 135543441221511 |
7 | 12300336630604 |
oct | 1714366061263 |
9 | 413813175387 |
10 | 130524144307 |
11 | 5039a527547 |
12 | 21368331897 |
13 | c4016614ab |
14 | 6462d47dab |
15 | 35ddd9a807 |
hex | 1e63d862b3 |
130524144307 has 2 divisors, whose sum is σ = 130524144308. Its totient is φ = 130524144306.
The previous prime is 130524144281. The next prime is 130524144313. The reversal of 130524144307 is 703441425031.
It is a strong prime.
It is an emirp because it is prime and its reverse (703441425031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130524144307 is a prime.
It is not a weakly prime, because it can be changed into another prime (130524144007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65262072153 + 65262072154.
It is an arithmetic number, because the mean of its divisors is an integer number (65262072154).
Almost surely, 2130524144307 is an apocalyptic number.
130524144307 is a deficient number, since it is larger than the sum of its proper divisors (1).
130524144307 is an equidigital number, since it uses as much as digits as its factorization.
130524144307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 130524144307 its reverse (703441425031), we get a palindrome (833965569338).
The spelling of 130524144307 in words is "one hundred thirty billion, five hundred twenty-four million, one hundred forty-four thousand, three hundred seven".
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