1305314534241 has 24 divisors (see below), whose sum is σ = 1912240512000. Its totient is φ = 857858786496.

The previous prime is 1305314534239. The next prime is 1305314534243. The reversal of 1305314534241 is 1424354135031.

1305314534241 is a `hidden beast` number, since 1 + 3 + 0 + 531 + 45 + 3 + 42 + 41 = 666.

It is an interprime number because it is at equal distance from previous prime (1305314534239) and next prime (1305314534243).

It is not a de Polignac number, because 1305314534241 - 2¹ = 1305314534239 is a prime.

It is a super-2 number, since 2×1305314534241² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1305314534196 and 1305314534205.

It is not an unprimeable number, because it can be changed into a prime (1305314534243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 816400 + ... + 1810286.

It is an arithmetic number, because the mean of its divisors is an integer number (79676688000).

Almost surely, 2^{1305314534241} is an apocalyptic number.

It is an amenable number.

1305314534241 is a deficient number, since it is larger than the sum of its proper divisors (606925977759).

1305314534241 is a wasteful number, since it uses less digits than its factorization.

1305314534241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 995965 (or 995962 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 36.

Adding to 1305314534241 its reverse (1424354135031), we get a palindrome (2729668669272).

The spelling of 1305314534241 in words is "one trillion, three hundred five billion, three hundred fourteen million, five hundred thirty-four thousand, two hundred forty-one".