Base | Representation |
---|---|
bin | 10010111111101011001… |
… | …010100111100110101011 |
3 | 11121210021000211212201102 |
4 | 102333223022213212223 |
5 | 132341244023120412 |
6 | 2435353404512015 |
7 | 163210026231662 |
oct | 22775312474653 |
9 | 4553230755642 |
10 | 1305320520107 |
11 | 46364644974a |
12 | 190b9124b60b |
13 | 96125489ba6 |
14 | 4726c041dd9 |
15 | 23e4b0908c2 |
hex | 12feb2a79ab |
1305320520107 has 2 divisors, whose sum is σ = 1305320520108. Its totient is φ = 1305320520106.
The previous prime is 1305320520089. The next prime is 1305320520113. The reversal of 1305320520107 is 7010250235031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1305320520107 - 28 = 1305320519851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1305320520107.
It is not a weakly prime, because it can be changed into another prime (1305320520407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652660260053 + 652660260054.
It is an arithmetic number, because the mean of its divisors is an integer number (652660260054).
Almost surely, 21305320520107 is an apocalyptic number.
1305320520107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305320520107 is an equidigital number, since it uses as much as digits as its factorization.
1305320520107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 29.
Adding to 1305320520107 its reverse (7010250235031), we get a palindrome (8315570755138).
The spelling of 1305320520107 in words is "one trillion, three hundred five billion, three hundred twenty million, five hundred twenty thousand, one hundred seven".
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