Base | Representation |
---|---|
bin | 11000010100000101… |
… | …11001011000011001 |
3 | 1020200201100010021011 |
4 | 30022002321120121 |
5 | 203213134331434 |
6 | 5555140213521 |
7 | 641322232024 |
oct | 141202713031 |
9 | 36621303234 |
10 | 13053433369 |
11 | 5599360769 |
12 | 264369a2a1 |
13 | 130048ca92 |
14 | 8bb8b81bb |
15 | 515ea8e64 |
hex | 30a0b9619 |
13053433369 has 2 divisors, whose sum is σ = 13053433370. Its totient is φ = 13053433368.
The previous prime is 13053433313. The next prime is 13053433373. The reversal of 13053433369 is 96333435031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12687093769 + 366339600 = 112637^2 + 19140^2 .
It is a cyclic number.
It is not a de Polignac number, because 13053433369 - 221 = 13051336217 is a prime.
It is a super-2 number, since 2×130534333692 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13053436369) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6526716684 + 6526716685.
It is an arithmetic number, because the mean of its divisors is an integer number (6526716685).
Almost surely, 213053433369 is an apocalyptic number.
It is an amenable number.
13053433369 is a deficient number, since it is larger than the sum of its proper divisors (1).
13053433369 is an equidigital number, since it uses as much as digits as its factorization.
13053433369 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 262440, while the sum is 40.
The spelling of 13053433369 in words is "thirteen billion, fifty-three million, four hundred thirty-three thousand, three hundred sixty-nine".
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