130534423454002 has 4 divisors (see below), whose sum is σ = 195801635181006. Its totient is φ = 65267211727000.

The previous prime is 130534423453921. The next prime is 130534423454033. The reversal of 130534423454002 is 200454324435031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 82697544004761 + 47836879449241 = 9093819^2 + 6916421^2 .

It is a super-3 number, since 3×130534423454002³ (a number of 43 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32633605863499 + ... + 32633605863502.

Almost surely, 2^{130534423454002} is an apocalyptic number.

130534423454002 is a deficient number, since it is larger than the sum of its proper divisors (65267211727004).

130534423454002 is an equidigital number, since it uses as much as digits as its factorization.

130534423454002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65267211727003.

The product of its (nonzero) digits is 691200, while the sum is 40.

Adding to 130534423454002 its reverse (200454324435031), we get a palindrome (330988747889033).

The spelling of 130534423454002 in words is "one hundred thirty trillion, five hundred thirty-four billion, four hundred twenty-three million, four hundred fifty-four thousand, two".