Base | Representation |
---|---|
bin | 10010111111110001010… |
… | …111010101010011011001 |
3 | 11121210112021112102200202 |
4 | 102333301113111103121 |
5 | 132342002134010223 |
6 | 2435412001511545 |
7 | 163212431206631 |
oct | 22776127252331 |
9 | 4553467472622 |
10 | 1305424516313 |
11 | 46369a11a625 |
12 | 1910000425b5 |
13 | 96140b9c5c8 |
14 | 4727bb936c1 |
15 | 23e55284428 |
hex | 12ff15d54d9 |
1305424516313 has 2 divisors, whose sum is σ = 1305424516314. Its totient is φ = 1305424516312.
The previous prime is 1305424516241. The next prime is 1305424516411. The reversal of 1305424516313 is 3136154245031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1262944420864 + 42480095449 = 1123808^2 + 206107^2 .
It is a cyclic number.
It is not a de Polignac number, because 1305424516313 - 216 = 1305424450777 is a prime.
It is a super-2 number, since 2×13054245163132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1305424516013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652712258156 + 652712258157.
It is an arithmetic number, because the mean of its divisors is an integer number (652712258157).
Almost surely, 21305424516313 is an apocalyptic number.
It is an amenable number.
1305424516313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305424516313 is an equidigital number, since it uses as much as digits as its factorization.
1305424516313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 38.
The spelling of 1305424516313 in words is "one trillion, three hundred five billion, four hundred twenty-four million, five hundred sixteen thousand, three hundred thirteen".
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