Base | Representation |
---|---|
bin | 10010111111110001111… |
… | …111011110110110000001 |
3 | 11121210120000100011001122 |
4 | 102333301333132312001 |
5 | 132342012332304103 |
6 | 2435413015242025 |
7 | 163212616523405 |
oct | 22776177366601 |
9 | 4553500304048 |
10 | 1305435041153 |
11 | 4636a5059041 |
12 | 191003679315 |
13 | 96143116019 |
14 | 4727d333105 |
15 | 23e56162b38 |
hex | 12ff1fded81 |
1305435041153 has 2 divisors, whose sum is σ = 1305435041154. Its totient is φ = 1305435041152.
The previous prime is 1305435041107. The next prime is 1305435041171. The reversal of 1305435041153 is 3511405345031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 718812317584 + 586622723569 = 847828^2 + 765913^2 .
It is a cyclic number.
It is not a de Polignac number, because 1305435041153 - 214 = 1305435024769 is a prime.
It is not a weakly prime, because it can be changed into another prime (1305435040153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652717520576 + 652717520577.
It is an arithmetic number, because the mean of its divisors is an integer number (652717520577).
Almost surely, 21305435041153 is an apocalyptic number.
It is an amenable number.
1305435041153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305435041153 is an equidigital number, since it uses as much as digits as its factorization.
1305435041153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 1305435041153 in words is "one trillion, three hundred five billion, four hundred thirty-five million, forty-one thousand, one hundred fifty-three".
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