Base | Representation |
---|---|
bin | 10010111111110010111… |
… | …000101010011111010001 |
3 | 11121210121001112201100021 |
4 | 102333302320222133101 |
5 | 132342030201443212 |
6 | 2435414312423441 |
7 | 163213161114634 |
oct | 22776270523721 |
9 | 4553531481307 |
10 | 1305450031057 |
11 | 463702567197 |
12 | 1910086a7b81 |
13 | 96146263ba3 |
14 | 47281315c1b |
15 | 23e57624307 |
hex | 12ff2e2a7d1 |
1305450031057 has 2 divisors, whose sum is σ = 1305450031058. Its totient is φ = 1305450031056.
The previous prime is 1305450031009. The next prime is 1305450031129. The reversal of 1305450031057 is 7501300545031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 915544699281 + 389905331776 = 956841^2 + 624424^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1305450031057 is a prime.
It is not a weakly prime, because it can be changed into another prime (1305450031957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652725015528 + 652725015529.
It is an arithmetic number, because the mean of its divisors is an integer number (652725015529).
Almost surely, 21305450031057 is an apocalyptic number.
It is an amenable number.
1305450031057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305450031057 is an equidigital number, since it uses as much as digits as its factorization.
1305450031057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31500, while the sum is 34.
Adding to 1305450031057 its reverse (7501300545031), we get a palindrome (8806750576088).
The spelling of 1305450031057 in words is "one trillion, three hundred five billion, four hundred fifty million, thirty-one thousand, fifty-seven".
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