Base | Representation |
---|---|
bin | 10010111111110011100… |
… | …000101001010110000100 |
3 | 11121210121210021012200020 |
4 | 102333303200221112010 |
5 | 132342040342342012 |
6 | 2435415325215140 |
7 | 163213346160000 |
oct | 22776340512604 |
9 | 4553553235606 |
10 | 1305460512132 |
11 | 463708475837 |
12 | 1910101014b0 |
13 | 961484936ca |
14 | 47282883700 |
15 | 23e584e4a8c |
hex | 12ff3829584 |
1305460512132 has 120 divisors (see below), whose sum is σ = 3554860781472. Its totient is φ = 372850329600.
The previous prime is 1305460512071. The next prime is 1305460512157. The reversal of 1305460512132 is 2312150645031.
It is a junction number, because it is equal to n+sod(n) for n = 1305460512093 and 1305460512102.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 97118532 + ... + 97131972.
Almost surely, 21305460512132 is an apocalyptic number.
1305460512132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1305460512132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1777430390736).
1305460512132 is an abundant number, since it is smaller than the sum of its proper divisors (2249400269340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1305460512132 is a wasteful number, since it uses less digits than its factorization.
1305460512132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16847 (or 16824 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 33.
The spelling of 1305460512132 in words is "one trillion, three hundred five billion, four hundred sixty million, five hundred twelve thousand, one hundred thirty-two".
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