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130550121411 = 343516707137
BaseRepresentation
bin111100110010101100…
…1001100001111000011
3110110222021002022022220
41321211121030033003
54114331312341121
6135550210102123
712301103502603
oct1714531141703
9413867068286
10130550121411
115040315a526
1221374b7a943
13c406b58368
14646658ac03
1535e12cc6c6
hex1e6564c3c3

130550121411 has 4 divisors (see below), whose sum is σ = 174066828552. Its totient is φ = 87033414272.

The previous prime is 130550121389. The next prime is 130550121413. The reversal of 130550121411 is 114121055031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130550121411 - 214 = 130550105027 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130550121413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21758353566 + ... + 21758353571.

It is an arithmetic number, because the mean of its divisors is an integer number (43516707138).

Almost surely, 2130550121411 is an apocalyptic number.

130550121411 is a deficient number, since it is larger than the sum of its proper divisors (43516707141).

130550121411 is an equidigital number, since it uses as much as digits as its factorization.

130550121411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43516707140.

The product of its (nonzero) digits is 600, while the sum is 24.

Adding to 130550121411 its reverse (114121055031), we get a palindrome (244671176442).

The spelling of 130550121411 in words is "one hundred thirty billion, five hundred fifty million, one hundred twenty-one thousand, four hundred eleven".

Divisors: 1 3 43516707137 130550121411