Base | Representation |
---|---|
bin | 111100110010101101… |
… | …0011010110000011011 |
3 | 110110222021200122111220 |
4 | 1321211122122300123 |
5 | 4114331403134120 |
6 | 135550221023123 |
7 | 12301106312355 |
oct | 1714532326033 |
9 | 413867618456 |
10 | 130550443035 |
11 | 5040335a131 |
12 | 213750b4aa3 |
13 | c406c3b87c |
14 | 64666320d5 |
15 | 35e1342b40 |
hex | 1e6569ac1b |
130550443035 has 32 divisors (see below), whose sum is σ = 216443465280. Its totient is φ = 67113984000.
The previous prime is 130550443033. The next prime is 130550443063. The reversal of 130550443035 is 530344055031.
It is not a de Polignac number, because 130550443035 - 21 = 130550443033 is a prime.
It is a super-2 number, since 2×1305504430352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130550442987 and 130550443005.
It is not an unprimeable number, because it can be changed into a prime (130550443033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11755 + ... + 511115.
It is an arithmetic number, because the mean of its divisors is an integer number (6763858290).
Almost surely, 2130550443035 is an apocalyptic number.
130550443035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
130550443035 is a deficient number, since it is larger than the sum of its proper divisors (85893022245).
130550443035 is a wasteful number, since it uses less digits than its factorization.
130550443035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 499999.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 130550443035 its reverse (530344055031), we get a palindrome (660894498066).
The spelling of 130550443035 in words is "one hundred thirty billion, five hundred fifty million, four hundred forty-three thousand, thirty-five".
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