Base | Representation |
---|---|
bin | 11000010100010010… |
… | …01110001110001001 |
3 | 1020200211110100220212 |
4 | 30022021032032021 |
5 | 203214100412333 |
6 | 5555235530505 |
7 | 641342306345 |
oct | 141211161611 |
9 | 36624410825 |
10 | 13055091593 |
11 | 559a2935a5 |
12 | 2644159a35 |
13 | 130092078b |
14 | 8bbbca625 |
15 | 5161d5448 |
hex | 30a24e389 |
13055091593 has 2 divisors, whose sum is σ = 13055091594. Its totient is φ = 13055091592.
The previous prime is 13055091587. The next prime is 13055091611. The reversal of 13055091593 is 39519055031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11389798729 + 1665292864 = 106723^2 + 40808^2 .
It is a cyclic number.
It is not a de Polignac number, because 13055091593 - 212 = 13055087497 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13055091593.
It is not a weakly prime, because it can be changed into another prime (13055091523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527545796 + 6527545797.
It is an arithmetic number, because the mean of its divisors is an integer number (6527545797).
Almost surely, 213055091593 is an apocalyptic number.
It is an amenable number.
13055091593 is a deficient number, since it is larger than the sum of its proper divisors (1).
13055091593 is an equidigital number, since it uses as much as digits as its factorization.
13055091593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 91125, while the sum is 41.
The spelling of 13055091593 in words is "thirteen billion, fifty-five million, ninety-one thousand, five hundred ninety-three".
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