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130551000163 = 743175707941
BaseRepresentation
bin111100110010101110…
…0100010110001100011
3110110222022201221202021
41321211130202301203
54114332024001123
6135550241002311
712301114122553
oct1714534426143
9413868657667
10130551000163
11504036aa771
1221375323397
13c4070a532c
146466739163
1535e1402c5d
hex1e65722c63

130551000163 has 4 divisors (see below), whose sum is σ = 130726708848. Its totient is φ = 130375291480.

The previous prime is 130551000157. The next prime is 130551000169. The reversal of 130551000163 is 361000155031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (130551000157) and next prime (130551000169).

It is a cyclic number.

It is not a de Polignac number, because 130551000163 - 25 = 130551000131 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130551000169) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87853228 + ... + 87854713.

It is an arithmetic number, because the mean of its divisors is an integer number (32681677212).

Almost surely, 2130551000163 is an apocalyptic number.

130551000163 is a deficient number, since it is larger than the sum of its proper divisors (175708685).

130551000163 is an equidigital number, since it uses as much as digits as its factorization.

130551000163 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175708684.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 130551000163 its reverse (361000155031), we get a palindrome (491551155194).

The spelling of 130551000163 in words is "one hundred thirty billion, five hundred fifty-one million, one hundred sixty-three", and thus it is an aban number.

Divisors: 1 743 175707941 130551000163