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130552314443 = 131996582553
BaseRepresentation
bin111100110010110000…
…1100011101001001011
3110110222102012201121022
41321211201203221023
54114332343030233
6135550325103055
712301131235355
oct1714541435113
9413872181538
10130552314443
1150404418151
1221375857a8b
13c407445605
14646699c0d5
1535e15b2398
hex1e65863a4b

130552314443 has 4 divisors (see below), whose sum is σ = 131548897128. Its totient is φ = 129555731760.

The previous prime is 130552314439. The next prime is 130552314449. The reversal of 130552314443 is 344413255031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130552314443 - 22 = 130552314439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130552314449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 498291146 + ... + 498291407.

It is an arithmetic number, because the mean of its divisors is an integer number (32887224282).

Almost surely, 2130552314443 is an apocalyptic number.

130552314443 is a deficient number, since it is larger than the sum of its proper divisors (996582685).

130552314443 is an equidigital number, since it uses as much as digits as its factorization.

130552314443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 996582684.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 130552314443 its reverse (344413255031), we get a palindrome (474965569474).

The spelling of 130552314443 in words is "one hundred thirty billion, five hundred fifty-two million, three hundred fourteen thousand, four hundred forty-three".

Divisors: 1 131 996582553 130552314443