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130553231089 is a prime number
BaseRepresentation
bin111100110010110010…
…1000011011011110001
3110110222110221022000011
41321211211003123301
54114333111343324
6135550400454521
712301142103661
oct1714545033361
9413873838004
10130553231089
1150404993906
122137601a441
13c4076a68c8
146466b5a1a1
1535e16e3c94
hex1e659436f1

130553231089 has 2 divisors, whose sum is σ = 130553231090. Its totient is φ = 130553231088.

The previous prime is 130553231077. The next prime is 130553231117. The reversal of 130553231089 is 980132355031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121521960000 + 9031271089 = 348600^2 + 95033^2 .

It is a cyclic number.

It is not a de Polignac number, because 130553231089 - 217 = 130553100017 is a prime.

It is a super-2 number, since 2×1305532310892 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130553231009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65276615544 + 65276615545.

It is an arithmetic number, because the mean of its divisors is an integer number (65276615545).

Almost surely, 2130553231089 is an apocalyptic number.

It is an amenable number.

130553231089 is a deficient number, since it is larger than the sum of its proper divisors (1).

130553231089 is an equidigital number, since it uses as much as digits as its factorization.

130553231089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 40.

The spelling of 130553231089 in words is "one hundred thirty billion, five hundred fifty-three million, two hundred thirty-one thousand, eighty-nine".