Base | Representation |
---|---|
bin | 111100110010110010… |
… | …1000110101010111011 |
3 | 110110222110221222012012 |
4 | 1321211211012222323 |
5 | 4114333112304342 |
6 | 135550401040135 |
7 | 12301142160431 |
oct | 1714545065273 |
9 | 413873858165 |
10 | 130553244347 |
11 | 504049a2869 |
12 | 2137602604b |
13 | c4076ac956 |
14 | 6466b60d51 |
15 | 35e16e7b82 |
hex | 1e65946abb |
130553244347 has 2 divisors, whose sum is σ = 130553244348. Its totient is φ = 130553244346.
The previous prime is 130553244317. The next prime is 130553244359. The reversal of 130553244347 is 743442355031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130553244347 is a prime.
It is not a weakly prime, because it can be changed into another prime (130553244317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65276622173 + 65276622174.
It is an arithmetic number, because the mean of its divisors is an integer number (65276622174).
Almost surely, 2130553244347 is an apocalyptic number.
130553244347 is a deficient number, since it is larger than the sum of its proper divisors (1).
130553244347 is an equidigital number, since it uses as much as digits as its factorization.
130553244347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 41.
Adding to 130553244347 its reverse (743442355031), we get a palindrome (873995599378).
The spelling of 130553244347 in words is "one hundred thirty billion, five hundred fifty-three million, two hundred forty-four thousand, three hundred forty-seven".
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