Search a number
-
+
13055420144321 = 72467180156763
BaseRepresentation
bin1011110111111011001110…
…1011100001101011000001
31201020002022200021120010022
42331332303223201223001
53202400000024104241
643433324402343225
72515136324143232
oct275766353415301
951202280246108
1013055420144321
114183855354465
12156a28995ab15
1373917562c319
14331c58543089
15179904cc554b
hexbdfb3ae1ac1

13055420144321 has 4 divisors (see below), whose sum is σ = 13055600373552. Its totient is φ = 13055239915092.

The previous prime is 13055420144317. The next prime is 13055420144413. The reversal of 13055420144321 is 12344102455031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13055420144321 - 22 = 13055420144317 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13055420144521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90005915 + ... + 90150848.

It is an arithmetic number, because the mean of its divisors is an integer number (3263900093388).

Almost surely, 213055420144321 is an apocalyptic number.

It is an amenable number.

13055420144321 is a deficient number, since it is larger than the sum of its proper divisors (180229231).

13055420144321 is an equidigital number, since it uses as much as digits as its factorization.

13055420144321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 180229230.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 13055420144321 its reverse (12344102455031), we get a palindrome (25399522599352).

The spelling of 13055420144321 in words is "thirteen trillion, fifty-five billion, four hundred twenty million, one hundred forty-four thousand, three hundred twenty-one".

Divisors: 1 72467 180156763 13055420144321