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13056077422049 is a prime number
BaseRepresentation
bin1011110111111101101011…
…0110110101110111100001
31201020011000111001201122212
42331333122312311313201
53202402321310001144
643433513522211505
72515161525000644
oct275773266656741
951204014051585
1013056077422049
1141840623739a2
12156a431ab3b95
1373924b860a5c
14331cbb959a5b
1517994285949e
hexbdfdadb5de1

13056077422049 has 2 divisors, whose sum is σ = 13056077422050. Its totient is φ = 13056077422048.

The previous prime is 13056077422021. The next prime is 13056077422081. The reversal of 13056077422049 is 94022477065031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10666756000000 + 2389321422049 = 3266000^2 + 1545743^2 .

It is a cyclic number.

It is not a de Polignac number, because 13056077422049 - 216 = 13056077356513 is a prime.

It is a super-2 number, since 2×130560774220492 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13056077421988 and 13056077422006.

It is not a weakly prime, because it can be changed into another prime (13056077422849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6528038711024 + 6528038711025.

It is an arithmetic number, because the mean of its divisors is an integer number (6528038711025).

Almost surely, 213056077422049 is an apocalyptic number.

It is an amenable number.

13056077422049 is a deficient number, since it is larger than the sum of its proper divisors (1).

13056077422049 is an equidigital number, since it uses as much as digits as its factorization.

13056077422049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 50.

The spelling of 13056077422049 in words is "thirteen trillion, fifty-six billion, seventy-seven million, four hundred twenty-two thousand, forty-nine".