Base | Representation |
---|---|
bin | 111100110011111110… |
… | …0110000110101011001 |
3 | 110111002020202210210011 |
4 | 1321213330300311121 |
5 | 4114423302011133 |
6 | 135554341121521 |
7 | 12302134122433 |
oct | 1714774606531 |
9 | 414066683704 |
10 | 130593000793 |
11 | 50425387432 |
12 | 213873b92a1 |
13 | c4129bc688 |
14 | 646c14d653 |
15 | 35e4e4c6cd |
hex | 1e67f30d59 |
130593000793 has 2 divisors, whose sum is σ = 130593000794. Its totient is φ = 130593000792.
The previous prime is 130593000763. The next prime is 130593000803. The reversal of 130593000793 is 397000395031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66901374409 + 63691626384 = 258653^2 + 252372^2 .
It is a cyclic number.
It is not a de Polignac number, because 130593000793 - 213 = 130592992601 is a prime.
It is a super-2 number, since 2×1305930007932 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130593000763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65296500396 + 65296500397.
It is an arithmetic number, because the mean of its divisors is an integer number (65296500397).
Almost surely, 2130593000793 is an apocalyptic number.
It is an amenable number.
130593000793 is a deficient number, since it is larger than the sum of its proper divisors (1).
130593000793 is an equidigital number, since it uses as much as digits as its factorization.
130593000793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76545, while the sum is 40.
The spelling of 130593000793 in words is "one hundred thirty billion, five hundred ninety-three million, seven hundred ninety-three", and thus it is an aban number.
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