Base | Representation |
---|---|
bin | 10011000000010110101… |
… | …010101000011000000001 |
3 | 11121212010220010011122111 |
4 | 103000112222220120001 |
5 | 132344242341112121 |
6 | 2435554035135321 |
7 | 163234100436631 |
oct | 23002652503001 |
9 | 4555126104574 |
10 | 1306050332161 |
11 | 463990400303 |
12 | 191155744541 |
13 | 96210736843 |
14 | 472dad3a6c1 |
15 | 23e901a12e1 |
hex | 13016aa8601 |
1306050332161 has 4 divisors (see below), whose sum is σ = 1306068663232. Its totient is φ = 1306032001092.
The previous prime is 1306050332149. The next prime is 1306050332201. The reversal of 1306050332161 is 1612330506031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1306050332161 - 229 = 1305513461249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1306050332131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9058245 + ... + 9201298.
It is an arithmetic number, because the mean of its divisors is an integer number (326517165808).
Almost surely, 21306050332161 is an apocalyptic number.
It is an amenable number.
1306050332161 is a deficient number, since it is larger than the sum of its proper divisors (18331071).
1306050332161 is an equidigital number, since it uses as much as digits as its factorization.
1306050332161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18331070.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 1306050332161 its reverse (1612330506031), we get a palindrome (2918380838192).
The spelling of 1306050332161 in words is "one trillion, three hundred six billion, fifty million, three hundred thirty-two thousand, one hundred sixty-one".
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