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13062603242441 is a prime number
BaseRepresentation
bin1011111000010101111111…
…0100110111101111001001
31201020202212021112202022102
42332011133310313233021
53203004202412224231
643440513241203145
72515512325363244
oct276053764675711
951222767482272
1013062603242441
114186900a97395
12156b7534904b5
13739a4b85233c
1433233a52225b
15179bc570aacb
hexbe15fd37bc9

13062603242441 has 2 divisors, whose sum is σ = 13062603242442. Its totient is φ = 13062603242440.

The previous prime is 13062603242419. The next prime is 13062603242537. The reversal of 13062603242441 is 14424230626031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10046389516816 + 3016213725625 = 3169604^2 + 1736725^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13062603242441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13062603242395 and 13062603242404.

It is not a weakly prime, because it can be changed into another prime (13062603242401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6531301621220 + 6531301621221.

It is an arithmetic number, because the mean of its divisors is an integer number (6531301621221).

Almost surely, 213062603242441 is an apocalyptic number.

It is an amenable number.

13062603242441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13062603242441 is an equidigital number, since it uses as much as digits as its factorization.

13062603242441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 38.

Adding to 13062603242441 its reverse (14424230626031), we get a palindrome (27486833868472).

The spelling of 13062603242441 in words is "thirteen trillion, sixty-two billion, six hundred three million, two hundred forty-two thousand, four hundred forty-one".