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13062603261361 = 103126821390887
BaseRepresentation
bin1011111000010101111111…
…0100111100010110110001
31201020202212021120201021011
42332011133310330112301
53203004202413330421
643440513241430521
72515512325502353
oct276053764742661
951222767521234
1013062603261361
114186900aaa625
12156b75349b441
13739a4b85ab34
1433233a5290d3
15179bc57114e1
hexbe15fd3c5b1

13062603261361 has 4 divisors (see below), whose sum is σ = 13189424652352. Its totient is φ = 12935781870372.

The previous prime is 13062603261341. The next prime is 13062603261373. The reversal of 13062603261361 is 16316230626031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13062603261361 - 211 = 13062603259313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13062603261341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63410695341 + ... + 63410695546.

It is an arithmetic number, because the mean of its divisors is an integer number (3297356163088).

Almost surely, 213062603261361 is an apocalyptic number.

It is an amenable number.

13062603261361 is a deficient number, since it is larger than the sum of its proper divisors (126821390991).

13062603261361 is a wasteful number, since it uses less digits than its factorization.

13062603261361 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 126821390990.

The product of its (nonzero) digits is 139968, while the sum is 40.

Adding to 13062603261361 its reverse (16316230626031), we get a palindrome (29378833887392).

The spelling of 13062603261361 in words is "thirteen trillion, sixty-two billion, six hundred three million, two hundred sixty-one thousand, three hundred sixty-one".

Divisors: 1 103 126821390887 13062603261361