Base | Representation |
---|---|
bin | 1011111000011000111110… |
… | …1001011001010000001001 |
3 | 1201020211221012012201011012 |
4 | 2332012033221121100021 |
5 | 3203012323304242421 |
6 | 43441125021213305 |
7 | 2515541236660241 |
oct | 276061751312011 |
9 | 51224835181135 |
10 | 13063405540361 |
11 | 4187182957720 |
12 | 156b938101235 |
13 | 739b48b2b137 |
14 | 3323b4cc8b21 |
15 | 179c20d8895b |
hex | be18fa59409 |
13063405540361 has 32 divisors (see below), whose sum is σ = 15026325534720. Its totient is φ = 11231831606400.
The previous prime is 13063405540333. The next prime is 13063405540379. The reversal of 13063405540361 is 16304550436031.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13063405540361 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13063405542361) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 311777165 + ... + 311819061.
It is an arithmetic number, because the mean of its divisors is an integer number (469572672960).
Almost surely, 213063405540361 is an apocalyptic number.
13063405540361 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13063405540361 is a deficient number, since it is larger than the sum of its proper divisors (1962919994359).
13063405540361 is a wasteful number, since it uses less digits than its factorization.
13063405540361 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44405.
The product of its (nonzero) digits is 388800, while the sum is 41.
Adding to 13063405540361 its reverse (16304550436031), we get a palindrome (29367955976392).
The spelling of 13063405540361 in words is "thirteen trillion, sixty-three billion, four hundred five million, five hundred forty thousand, three hundred sixty-one".
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