Base | Representation |
---|---|
bin | 1011111000100111000111… |
… | …1110000100101100101011 |
3 | 1201021012201211001221020112 |
4 | 2332021301332010230223 |
5 | 3203043112332041021 |
6 | 43442553501444535 |
7 | 2516034314362052 |
oct | 276116176045453 |
9 | 51235654057215 |
10 | 13067202612011 |
11 | 4188851238869 |
12 | 157061787074b |
13 | 73a3026ab6b2 |
14 | 3326552d7399 |
15 | 179d943c6d5b |
hex | be271f84b2b |
13067202612011 has 4 divisors (see below), whose sum is σ = 13246205387592. Its totient is φ = 12888199836432.
The previous prime is 13067202611959. The next prime is 13067202612019. The reversal of 13067202612011 is 11021620276031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13067202612011 - 242 = 8669156100907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13067202612019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89501387681 + ... + 89501387826.
It is an arithmetic number, because the mean of its divisors is an integer number (3311551346898).
Almost surely, 213067202612011 is an apocalyptic number.
13067202612011 is a deficient number, since it is larger than the sum of its proper divisors (179002775581).
13067202612011 is an equidigital number, since it uses as much as digits as its factorization.
13067202612011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179002775580.
The product of its (nonzero) digits is 6048, while the sum is 32.
Adding to 13067202612011 its reverse (11021620276031), we get a palindrome (24088822888042).
The spelling of 13067202612011 in words is "thirteen trillion, sixty-seven billion, two hundred two million, six hundred twelve thousand, eleven".
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