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13074208063441 = 71867744009063
BaseRepresentation
bin1011111001000001001110…
…0001101111111111010001
31201021212211001001201222121
42332100103201233333101
53203201434231012231
643450112552534241
72516403030624520
oct276202341577721
951255731051877
1013074208063441
114190816676148
121571a519b1381
1373ab7ab72a25
14332b1b8724b7
1517a15441b311
hexbe41386ffd1

13074208063441 has 4 divisors (see below), whose sum is σ = 14941952072512. Its totient is φ = 11206464054372.

The previous prime is 13074208063379. The next prime is 13074208063487. The reversal of 13074208063441 is 14436080247031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13074208063441 - 217 = 13074207932369 is a prime.

It is a super-2 number, since 2×130742080634412 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13074208069441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 933872004525 + ... + 933872004538.

It is an arithmetic number, because the mean of its divisors is an integer number (3735488018128).

Almost surely, 213074208063441 is an apocalyptic number.

It is an amenable number.

13074208063441 is a deficient number, since it is larger than the sum of its proper divisors (1867744009071).

13074208063441 is an equidigital number, since it uses as much as digits as its factorization.

13074208063441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1867744009070.

The product of its (nonzero) digits is 387072, while the sum is 43.

The spelling of 13074208063441 in words is "thirteen trillion, seventy-four billion, two hundred eight million, sixty-three thousand, four hundred forty-one".

Divisors: 1 7 1867744009063 13074208063441