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130862556925547 is a prime number
BaseRepresentation
bin11101110000010011010000…
…001110000100111001101011
3122011100100010121001002221212
4131300103100032010321223
5114123023004033104142
61142153232334223335
736364336103460566
oct3560232016047153
9564310117032855
10130862556925547
1138773553893a97
1212816059654b4b
13580339492c925
142445ad28054dd
15101e07e810d82
hex7704d0384e6b

130862556925547 has 2 divisors, whose sum is σ = 130862556925548. Its totient is φ = 130862556925546.

The previous prime is 130862556925433. The next prime is 130862556925567. The reversal of 130862556925547 is 745529655268031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130862556925547 - 228 = 130862288490091 is a prime.

It is not a weakly prime, because it can be changed into another prime (130862556925567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65431278462773 + 65431278462774.

It is an arithmetic number, because the mean of its divisors is an integer number (65431278462774).

It is a 3-persistent number, because k⋅130862556925547 is pandigital for 1 ≤ k ≤ 3, but not for k = 4.

Almost surely, 2130862556925547 is an apocalyptic number.

130862556925547 is a deficient number, since it is larger than the sum of its proper divisors (1).

130862556925547 is an equidigital number, since it uses as much as digits as its factorization.

130862556925547 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 544320000, while the sum is 68.

The spelling of 130862556925547 in words is "one hundred thirty trillion, eight hundred sixty-two billion, five hundred fifty-six million, nine hundred twenty-five thousand, five hundred forty-seven".