Base | Representation |
---|---|
bin | 11101110000010011010000… |
… | …001110000100111001101011 |
3 | 122011100100010121001002221212 |
4 | 131300103100032010321223 |
5 | 114123023004033104142 |
6 | 1142153232334223335 |
7 | 36364336103460566 |
oct | 3560232016047153 |
9 | 564310117032855 |
10 | 130862556925547 |
11 | 38773553893a97 |
12 | 12816059654b4b |
13 | 580339492c925 |
14 | 2445ad28054dd |
15 | 101e07e810d82 |
hex | 7704d0384e6b |
130862556925547 has 2 divisors, whose sum is σ = 130862556925548. Its totient is φ = 130862556925546.
The previous prime is 130862556925433. The next prime is 130862556925567. The reversal of 130862556925547 is 745529655268031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130862556925547 - 228 = 130862288490091 is a prime.
It is not a weakly prime, because it can be changed into another prime (130862556925567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65431278462773 + 65431278462774.
It is an arithmetic number, because the mean of its divisors is an integer number (65431278462774).
It is a 3-persistent number, because k⋅130862556925547 is pandigital for 1 ≤ k ≤ 3, but not for k = 4.
Almost surely, 2130862556925547 is an apocalyptic number.
130862556925547 is a deficient number, since it is larger than the sum of its proper divisors (1).
130862556925547 is an equidigital number, since it uses as much as digits as its factorization.
130862556925547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320000, while the sum is 68.
The spelling of 130862556925547 in words is "one hundred thirty trillion, eight hundred sixty-two billion, five hundred fifty-six million, nine hundred twenty-five thousand, five hundred forty-seven".
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