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1310000110323 = 31741626494553
BaseRepresentation
bin10011000100000010000…
…101110101101011110011
311122020100011022200200120
4103010002011311223303
5132430340012012243
62441450012421323
7163434011133102
oct23040205655363
94566304280616
101310000110323
11465627a02083
12191a78477843
13966bcb22b98
144759373a039
1524121d05c83
hex13102175af3

1310000110323 has 16 divisors (see below), whose sum is σ = 1894519531296. Its totient is φ = 801913026560.

The previous prime is 1310000110303. The next prime is 1310000110333. The reversal of 1310000110323 is 3230110000131.

It is a cyclic number.

It is not a de Polignac number, because 1310000110323 - 25 = 1310000110291 is a prime.

It is a super-2 number, since 2×13100001103232 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1310000110303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 313245186 + ... + 313249367.

It is an arithmetic number, because the mean of its divisors is an integer number (118407470706).

Almost surely, 21310000110323 is an apocalyptic number.

1310000110323 is a deficient number, since it is larger than the sum of its proper divisors (584519420973).

1310000110323 is a wasteful number, since it uses less digits than its factorization.

1310000110323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 626494614.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1310000110323 its reverse (3230110000131), we get a palindrome (4540110110454).

The spelling of 1310000110323 in words is "one trillion, three hundred ten billion, one hundred ten thousand, three hundred twenty-three".

Divisors: 1 3 17 41 51 123 697 2091 626494553 1879483659 10650407401 25686276673 31951222203 77058830019 436666703441 1310000110323