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131000014113 = 361770772563
BaseRepresentation
bin111101000000000110…
…1011001010100100001
3110112010121122020002120
41322000031121110201
54121242000422423
6140103000534453
712315205514253
oct1720015312441
9415117566076
10131000014113
1150614102581
122147b781429
13c479118267
1464aa21bcd3
15361aa48ee3
hex1e80359521

131000014113 has 8 divisors (see below), whose sum is σ = 174949778208. Its totient is φ = 87191796384.

The previous prime is 131000014099. The next prime is 131000014139. The reversal of 131000014113 is 311410000131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131000014113 - 28 = 131000013857 is a prime.

It is a super-2 number, since 2×1310000141132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131000014092 and 131000014101.

It is not an unprimeable number, because it can be changed into a prime (131000014163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35384431 + ... + 35388132.

It is an arithmetic number, because the mean of its divisors is an integer number (21868722276).

Almost surely, 2131000014113 is an apocalyptic number.

It is an amenable number.

131000014113 is a deficient number, since it is larger than the sum of its proper divisors (43949764095).

131000014113 is an equidigital number, since it uses as much as digits as its factorization.

131000014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70773183.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 131000014113 its reverse (311410000131), we get a palindrome (442410014244).

The spelling of 131000014113 in words is "one hundred thirty-one billion, fourteen thousand, one hundred thirteen".

Divisors: 1 3 617 1851 70772563 212317689 43666671371 131000014113