131000040134003 has 4 divisors (see below), whose sum is σ = 131000685000240. Its totient is φ = 130999395267768.

The previous prime is 131000040133993. The next prime is 131000040134011. The reversal of 131000040134003 is 300431040000131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131000040134003 - 2⁶ = 131000040133939 is a prime.

It is a super-2 number, since 2×131000040134003² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131000040134063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 322128308 + ... + 322534721.

It is an arithmetic number, because the mean of its divisors is an integer number (32750171250060).

Almost surely, 2^{131000040134003} is an apocalyptic number.

131000040134003 is a deficient number, since it is larger than the sum of its proper divisors (644866237).

131000040134003 is an equidigital number, since it uses as much as digits as its factorization.

131000040134003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 644866236.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 131000040134003 its reverse (300431040000131), we get a palindrome (431431080134134).

The spelling of 131000040134003 in words is "one hundred thirty-one trillion, forty million, one hundred thirty-four thousand, three".