Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …110111111101110001011111 |
3 | 122011211111000001110222020220 |
4 | 131302103102313331301133 |
5 | 114132301040321224203 |
6 | 1142340330542412423 |
7 | 36410304060032454 |
oct | 3562232267756137 |
9 | 564744001428226 |
10 | 131000040414303 |
11 | 38816894716a75 |
12 | 12838828591113 |
13 | 5813335030cc8 |
14 | 244c615b2582b |
15 | 1022929644653 |
hex | 7724d2dfdc5f |
131000040414303 has 16 divisors (see below), whose sum is σ = 185573216621280. Its totient is φ = 82042895765376.
The previous prime is 131000040414283. The next prime is 131000040414319. The reversal of 131000040414303 is 303414040000131.
It is not a de Polignac number, because 131000040414303 - 210 = 131000040413279 is a prime.
It is a super-2 number, since 2×1310000404143032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000040414203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20347937200 + ... + 20347943637.
It is an arithmetic number, because the mean of its divisors is an integer number (11598326038830).
Almost surely, 2131000040414303 is an apocalyptic number.
131000040414303 is a deficient number, since it is larger than the sum of its proper divisors (54573176206977).
131000040414303 is a wasteful number, since it uses less digits than its factorization.
131000040414303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40695880906.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 131000040414303 its reverse (303414040000131), we get a palindrome (434414080414434).
The spelling of 131000040414303 in words is "one hundred thirty-one trillion, forty million, four hundred fourteen thousand, three hundred three".
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