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131000040414303 = 3293740695880837
BaseRepresentation
bin11101110010010011010010…
…110111111101110001011111
3122011211111000001110222020220
4131302103102313331301133
5114132301040321224203
61142340330542412423
736410304060032454
oct3562232267756137
9564744001428226
10131000040414303
1138816894716a75
1212838828591113
135813335030cc8
14244c615b2582b
151022929644653
hex7724d2dfdc5f

131000040414303 has 16 divisors (see below), whose sum is σ = 185573216621280. Its totient is φ = 82042895765376.

The previous prime is 131000040414283. The next prime is 131000040414319. The reversal of 131000040414303 is 303414040000131.

It is not a de Polignac number, because 131000040414303 - 210 = 131000040413279 is a prime.

It is a super-2 number, since 2×1310000404143032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000040414203) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20347937200 + ... + 20347943637.

It is an arithmetic number, because the mean of its divisors is an integer number (11598326038830).

Almost surely, 2131000040414303 is an apocalyptic number.

131000040414303 is a deficient number, since it is larger than the sum of its proper divisors (54573176206977).

131000040414303 is a wasteful number, since it uses less digits than its factorization.

131000040414303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40695880906.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 131000040414303 its reverse (303414040000131), we get a palindrome (434414080414434).

The spelling of 131000040414303 in words is "one hundred thirty-one trillion, forty million, four hundred fourteen thousand, three hundred three".

Divisors: 1 3 29 37 87 111 1073 3219 40695880837 122087642511 1180180544273 1505747590969 3540541632819 4517242772907 43666680138101 131000040414303