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1310001121303 = 71997101542603
BaseRepresentation
bin10011000100000010001…
…001101100100000010111
311122020100020020001111021
4103010002021230200113
5132430340241340203
62441450050222011
7163434022543420
oct23040211544027
94566306201437
101310001121303
114656285326a6
12191a78884907
13966c00b80b4
1447593920647
1524121e555bd
hex1310226c817

1310001121303 has 16 divisors (see below), whose sum is σ = 1592188030720. Its totient is φ = 1052793697536.

The previous prime is 1310001121271. The next prime is 1310001121327. The reversal of 1310001121303 is 3031211000131.

It is not a de Polignac number, because 1310001121303 - 25 = 1310001121271 is a prime.

It is a super-2 number, since 2×13100011213032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310001121003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50758401 + ... + 50784202.

It is an arithmetic number, because the mean of its divisors is an integer number (99511751920).

Almost surely, 21310001121303 is an apocalyptic number.

1310001121303 is a deficient number, since it is larger than the sum of its proper divisors (282186909417).

1310001121303 is a wasteful number, since it uses less digits than its factorization.

1310001121303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101542726.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1310001121303 its reverse (3031211000131), we get a palindrome (4341212121434).

The spelling of 1310001121303 in words is "one trillion, three hundred ten billion, one million, one hundred twenty-one thousand, three hundred three".

Divisors: 1 7 19 97 133 679 1843 12901 101542603 710798221 1929309457 9849632491 13505166199 68947427437 187143017329 1310001121303