Base | Representation |
---|---|
bin | 1011111010100001010110… |
… | …1100011001100100011010 |
3 | 1201101100102111212222122111 |
4 | 2332220111230121210122 |
5 | 3204112312114312102 |
6 | 43510021412142534 |
7 | 2521305364365364 |
oct | 276502554314432 |
9 | 51340374788574 |
10 | 13100014213402 |
11 | 41a0759563606 |
12 | 1576a54307a4a |
13 | 74043140344c |
14 | 334088d05d34 |
15 | 17ab64c7ccd7 |
hex | bea15b1991a |
13100014213402 has 8 divisors (see below), whose sum is σ = 19712800941876. Its totient is φ = 6529080566112.
The previous prime is 13100014213379. The next prime is 13100014213417. The reversal of 13100014213402 is 20431241000131.
13100014213402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 12544212651961 + 555801561441 = 3541781^2 + 745521^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×131000142134022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10463269513 + ... + 10463270764.
Almost surely, 213100014213402 is an apocalyptic number.
13100014213402 is a deficient number, since it is larger than the sum of its proper divisors (6612786728474).
13100014213402 is a wasteful number, since it uses less digits than its factorization.
13100014213402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20926540592.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 13100014213402 its reverse (20431241000131), we get a palindrome (33531255213533).
The spelling of 13100014213402 in words is "thirteen trillion, one hundred billion, fourteen million, two hundred thirteen thousand, four hundred two".
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