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131000304013427 is a prime number
BaseRepresentation
bin11101110010010011100010…
…100101100001000001110011
3122011211111200102111012021102
4131302103202211201001303
5114132302110311412202
61142340413040315015
736410313440424152
oct3562234245410163
9564744612435242
10131000304013427
1138816a0a498992
12128388a0912a6b
135813377825514
14244c63cb41599
151022942862d02
hex7724e2961073

131000304013427 has 2 divisors, whose sum is σ = 131000304013428. Its totient is φ = 131000304013426.

The previous prime is 131000304013387. The next prime is 131000304013433. The reversal of 131000304013427 is 724310403000131.

It is a strong prime.

It is an emirp because it is prime and its reverse (724310403000131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131000304013427 - 26 = 131000304013363 is a prime.

It is a super-2 number, since 2×1310003040134272 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131000304013427.

It is not a weakly prime, because it can be changed into another prime (131000304016427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500152006713 + 65500152006714.

It is an arithmetic number, because the mean of its divisors is an integer number (65500152006714).

Almost surely, 2131000304013427 is an apocalyptic number.

131000304013427 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000304013427 is an equidigital number, since it uses as much as digits as its factorization.

131000304013427 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 131000304013427 its reverse (724310403000131), we get a palindrome (855310707013558).

The spelling of 131000304013427 in words is "one hundred thirty-one trillion, three hundred four million, thirteen thousand, four hundred twenty-seven".