13100032040241 has 8 divisors (see below), whose sum is σ = 18386009881120. Its totient is φ = 8273704446432.

The previous prime is 13100032040239. The next prime is 13100032040269. The reversal of 13100032040241 is 14204023000131.

13100032040241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13100032040241 - 2¹ = 13100032040239 is a prime.

It is a super-2 number, since 2×13100032040241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13100032040941) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 114912561700 + ... + 114912561813.

It is an arithmetic number, because the mean of its divisors is an integer number (2298251235140).

Almost surely, 2^{13100032040241} is an apocalyptic number.

It is an amenable number.

13100032040241 is a deficient number, since it is larger than the sum of its proper divisors (5285977840879).

13100032040241 is a wasteful number, since it uses less digits than its factorization.

13100032040241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 229825123535.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13100032040241 its reverse (14204023000131), we get a palindrome (27304055040372).

The spelling of 13100032040241 in words is "thirteen trillion, one hundred billion, thirty-two million, forty thousand, two hundred forty-one".