Base | Representation |
---|---|
bin | 1011111010100001011011… |
… | …0001110111100110110011 |
3 | 1201101100110210011012101211 |
4 | 2332220112301313212303 |
5 | 3204112331300034441 |
6 | 43510023302340551 |
7 | 2521306005233524 |
oct | 276502661674663 |
9 | 51340423135354 |
10 | 13100032424371 |
11 | 41a07688717a2 |
12 | 1576a5a42a757 |
13 | 74043510b479 |
14 | 33408b4c684b |
15 | 17ab66678a81 |
hex | bea16c779b3 |
13100032424371 has 2 divisors, whose sum is σ = 13100032424372. Its totient is φ = 13100032424370.
The previous prime is 13100032424341. The next prime is 13100032424429. The reversal of 13100032424371 is 17342423000131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13100032424371 is a prime.
It is a super-2 number, since 2×131000324243712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13100032424341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550016212185 + 6550016212186.
It is an arithmetic number, because the mean of its divisors is an integer number (6550016212186).
Almost surely, 213100032424371 is an apocalyptic number.
13100032424371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100032424371 is an equidigital number, since it uses as much as digits as its factorization.
13100032424371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
The spelling of 13100032424371 in words is "thirteen trillion, one hundred billion, thirty-two million, four hundred twenty-four thousand, three hundred seventy-one".
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