131000403 has 8 divisors (see below), whose sum is σ = 178729408. Its totient is φ = 85302504.

The previous prime is 131000399. The next prime is 131000423. The reversal of 131000403 is 304000131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131000403 - 2² = 131000399 is a prime.

It is a super-2 number, since 2×131000403² = 34322211172324818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131000423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 507625 + ... + 507882.

It is an arithmetic number, because the mean of its divisors is an integer number (22341176).

Almost surely, 2^131000403 is an apocalyptic number.

131000403 is a deficient number, since it is larger than the sum of its proper divisors (47729005).

131000403 is a wasteful number, since it uses less digits than its factorization.

131000403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1015553.

The product of its (nonzero) digits is 36, while the sum is 12.

The square root of 131000403 is about 11445.5407473828. The cubic root of 131000403 is about 507.8758286111.

Adding to 131000403 its reverse (304000131), we get a palindrome (435000534).

The spelling of 131000403 in words is "one hundred thirty-one million, four hundred three", and thus it is an aban number.