Base | Representation |
---|---|
bin | 11101110010010011101001… |
… | …100100010001111011110011 |
3 | 122011211111222120212022222012 |
4 | 131302103221210101323303 |
5 | 114132302330302124341 |
6 | 1142340432422433135 |
7 | 36410316362045621 |
oct | 3562235144217363 |
9 | 564744876768865 |
10 | 131000421129971 |
11 | 38816a6a610318 |
12 | 12838913b927ab |
13 | 5813395b7cb53 |
14 | 244c65050a511 |
15 | 102294cc990eb |
hex | 7724e9911ef3 |
131000421129971 has 2 divisors, whose sum is σ = 131000421129972. Its totient is φ = 131000421129970.
The previous prime is 131000421129917. The next prime is 131000421130129. The reversal of 131000421129971 is 179921124000131.
Together with previous prime (131000421129917) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131000421129971 - 222 = 131000416935667 is a prime.
It is a super-2 number, since 2×1310004211299712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131000421122971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500210564985 + 65500210564986.
It is an arithmetic number, because the mean of its divisors is an integer number (65500210564986).
Almost surely, 2131000421129971 is an apocalyptic number.
131000421129971 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000421129971 is an equidigital number, since it uses as much as digits as its factorization.
131000421129971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27216, while the sum is 41.
The spelling of 131000421129971 in words is "one hundred thirty-one trillion, four hundred twenty-one million, one hundred twenty-nine thousand, nine hundred seventy-one".
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