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131000421129971 is a prime number
BaseRepresentation
bin11101110010010011101001…
…100100010001111011110011
3122011211111222120212022222012
4131302103221210101323303
5114132302330302124341
61142340432422433135
736410316362045621
oct3562235144217363
9564744876768865
10131000421129971
1138816a6a610318
1212838913b927ab
135813395b7cb53
14244c65050a511
15102294cc990eb
hex7724e9911ef3

131000421129971 has 2 divisors, whose sum is σ = 131000421129972. Its totient is φ = 131000421129970.

The previous prime is 131000421129917. The next prime is 131000421130129. The reversal of 131000421129971 is 179921124000131.

Together with previous prime (131000421129917) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131000421129971 - 222 = 131000416935667 is a prime.

It is a super-2 number, since 2×1310004211299712 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131000421122971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500210564985 + 65500210564986.

It is an arithmetic number, because the mean of its divisors is an integer number (65500210564986).

Almost surely, 2131000421129971 is an apocalyptic number.

131000421129971 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000421129971 is an equidigital number, since it uses as much as digits as its factorization.

131000421129971 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27216, while the sum is 41.

The spelling of 131000421129971 in words is "one hundred thirty-one trillion, four hundred twenty-one million, one hundred twenty-nine thousand, nine hundred seventy-one".