13100044032241 has 2 divisors, whose sum is σ = 13100044032242. Its totient is φ = 13100044032240.

The previous prime is 13100044032227. The next prime is 13100044032247. The reversal of 13100044032241 is 14223044000131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11756772304225 + 1343271728016 = 3428815^2 + 1158996^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100044032241 - 2¹³ = 13100044024049 is a prime.

It is a super-2 number, since 2×13100044032241² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13100044032247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550022016120 + 6550022016121.

It is an arithmetic number, because the mean of its divisors is an integer number (6550022016121).

Almost surely, 2^{13100044032241} is an apocalyptic number.

It is an amenable number.

13100044032241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100044032241 is an equidigital number, since it uses as much as digits as its factorization.

13100044032241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13100044032241 its reverse (14223044000131), we get a palindrome (27323088032372).

The spelling of 13100044032241 in words is "thirteen trillion, one hundred billion, forty-four million, thirty-two thousand, two hundred forty-one".