13100044124401 has 16 divisors (see below), whose sum is σ = 14210956555264. Its totient is φ = 12004021882944.

The previous prime is 13100044124339. The next prime is 13100044124429. The reversal of 13100044124401 is 10442144000131.

13100044124401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13100044124401 - 2¹³ = 13100044116209 is a prime.

It is a super-2 number, since 2×13100044124401² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100044121401) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 849441 + ... + 5188606.

It is an arithmetic number, because the mean of its divisors is an integer number (888184784704).

Almost surely, 2^{13100044124401} is an apocalyptic number.

It is an amenable number.

13100044124401 is a deficient number, since it is larger than the sum of its proper divisors (1110912430863).

13100044124401 is a wasteful number, since it uses less digits than its factorization.

13100044124401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6039280.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 13100044124401 its reverse (10442144000131), we get a palindrome (23542188124532).

The spelling of 13100044124401 in words is "thirteen trillion, one hundred billion, forty-four million, one hundred twenty-four thousand, four hundred one".