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131001021663 = 31117186720939
BaseRepresentation
bin111101000000001000…
…1001111010011011111
3110112010200112102012020
41322000101033103133
54121242230143123
6140103034311223
712315220211601
oct1720021172337
9415120472166
10131001021663
1150614730566
122147bb88513
13c4793aba45
1464aa401171
15361ab977e3
hex1e8044f4df

131001021663 has 16 divisors (see below), whose sum is σ = 174926394240. Its totient is φ = 87204927456.

The previous prime is 131001021631. The next prime is 131001021691. The reversal of 131001021663 is 366120100131.

It is not a de Polignac number, because 131001021663 - 25 = 131001021631 is a prime.

It is a super-2 number, since 2×1310010216632 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131002021663) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6245848 + ... + 6266786.

It is an arithmetic number, because the mean of its divisors is an integer number (10932899640).

Almost surely, 2131001021663 is an apocalyptic number.

131001021663 is a deficient number, since it is larger than the sum of its proper divisors (43925372577).

131001021663 is a wasteful number, since it uses less digits than its factorization.

131001021663 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23926.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 131001021663 its reverse (366120100131), we get a palindrome (497121121794).

The spelling of 131001021663 in words is "one hundred thirty-one billion, one million, twenty-one thousand, six hundred sixty-three".

Divisors: 1 3 1117 1867 3351 5601 20939 62817 2085439 6256317 23388863 39093113 70166589 117279339 43667007221 131001021663