131001100401422 has 16 divisors (see below), whose sum is σ = 198465336501120. Its totient is φ = 64846773554808.

The previous prime is 131001100401389. The next prime is 131001100401461. The reversal of 131001100401422 is 224104001100131.

It is a super-2 number, since 2×131001100401422² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001100401394 and 131001100401403.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 195995648 + ... + 196662899.

It is an arithmetic number, because the mean of its divisors is an integer number (12404083531320).

Almost surely, 2^{131001100401422} is an apocalyptic number.

131001100401422 is a deficient number, since it is larger than the sum of its proper divisors (67464236099698).

131001100401422 is a wasteful number, since it uses less digits than its factorization.

131001100401422 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 392660215.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 131001100401422 its reverse (224104001100131), we get a palindrome (355105101501553).

The spelling of 131001100401422 in words is "one hundred thirty-one trillion, one billion, one hundred million, four hundred one thousand, four hundred twenty-two".