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1310011102011 = 3436670367337
BaseRepresentation
bin10011000100000010101…
…111110001001100111011
311122020100221000010110010
4103010002233301030323
5132430400320231021
62441451044153003
7163434203432613
oct23040257611473
94566327003403
101310011102011
1146563312a317
12191a80098763
13966c21a0c41
1447594d9ba43
1524122c77976
hex13102bf133b

1310011102011 has 4 divisors (see below), whose sum is σ = 1746681469352. Its totient is φ = 873340734672.

The previous prime is 1310011101937. The next prime is 1310011102061. The reversal of 1310011102011 is 1102011100131.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-1310011102011 is a prime.

It is a super-2 number, since 2×13100111020112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310011102061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218335183666 + ... + 218335183671.

It is an arithmetic number, because the mean of its divisors is an integer number (436670367338).

Almost surely, 21310011102011 is an apocalyptic number.

1310011102011 is a deficient number, since it is larger than the sum of its proper divisors (436670367341).

1310011102011 is an equidigital number, since it uses as much as digits as its factorization.

1310011102011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 436670367340.

The product of its (nonzero) digits is 6, while the sum is 12.

Adding to 1310011102011 its reverse (1102011100131), we get a palindrome (2412022202142).

The spelling of 1310011102011 in words is "one trillion, three hundred ten billion, eleven million, one hundred two thousand, eleven".

Divisors: 1 3 436670367337 1310011102011