1310011232131 has 16 divisors (see below), whose sum is σ = 1604322768384. Its totient is φ = 1044083055744.

The previous prime is 1310011232119. The next prime is 1310011232143. The reversal of 1310011232131 is 1312321100131.

It is an interprime number because it is at equal distance from previous prime (1310011232119) and next prime (1310011232143).

It is a cyclic number.

It is not a de Polignac number, because 1310011232131 - 2⁷ = 1310011232003 is a prime.

It is a super-2 number, since 2×1310011232131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310011232099 and 1310011232108.

It is not an unprimeable number, because it can be changed into a prime (1310011232111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66306375 + ... + 66326128.

It is an arithmetic number, because the mean of its divisors is an integer number (100270173024).

Almost surely, 2^{1310011232131} is an apocalyptic number.

1310011232131 is a deficient number, since it is larger than the sum of its proper divisors (294311536253).

1310011232131 is a wasteful number, since it uses less digits than its factorization.

1310011232131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132632610.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1310011232131 its reverse (1312321100131), we get a palindrome (2622332332262).

The spelling of 1310011232131 in words is "one trillion, three hundred ten billion, eleven million, two hundred thirty-two thousand, one hundred thirty-one".