13100112332001 has 6 divisors (see below), whose sum is σ = 18922384479570. Its totient is φ = 8733408221328.

The previous prime is 13100112331987. The next prime is 13100112332023. The reversal of 13100112332001 is 10023321100131.

13100112332001 is a `hidden beast` number, since 1 + 310 + 0 + 11 + 23 + 320 + 0 + 1 = 666.

13100112332001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 11160844416225 + 1939267915776 = 3340785^2 + 1392576^2 .

It is a de Polignac number, because none of the positive numbers 2^k-13100112332001 is a prime.

It is a super-2 number, since 2×13100112332001² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13100112332051) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 727784018436 + ... + 727784018453.

It is an arithmetic number, because the mean of its divisors is an integer number (3153730746595).

Almost surely, 2^{13100112332001} is an apocalyptic number.

It is an amenable number.

13100112332001 is a deficient number, since it is larger than the sum of its proper divisors (5822272147569).

13100112332001 is a wasteful number, since it uses less digits than its factorization.

13100112332001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1455568036895 (or 1455568036892 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 13100112332001 its reverse (10023321100131), we get a palindrome (23123433432132).

The spelling of 13100112332001 in words is "thirteen trillion, one hundred billion, one hundred twelve million, three hundred thirty-two thousand, one".