1310012000299 has 2 divisors, whose sum is σ = 1310012000300. Its totient is φ = 1310012000298.

The previous prime is 1310012000267. The next prime is 1310012000303. The reversal of 1310012000299 is 9920002100131.

It is a strong prime.

It is an emirp because it is prime and its reverse (9920002100131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310012000299 - 2⁵ = 1310012000267 is a prime.

It is a super-2 number, since 2×1310012000299² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310012000249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006000149 + 655006000150.

It is an arithmetic number, because the mean of its divisors is an integer number (655006000150).

Almost surely, 2^{1310012000299} is an apocalyptic number.

1310012000299 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310012000299 is an equidigital number, since it uses as much as digits as its factorization.

1310012000299 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 28.

The spelling of 1310012000299 in words is "one trillion, three hundred ten billion, twelve million, two hundred ninety-nine", and thus it is an aban number.